destructor call explitly

using namespace std;   class Test { public:     Test()  { cout << "Constructor is executed\n"; }     ~Test() { cout << "Destructor is executed\n";  } };   int main() {     Test();  // Explicit call to constructor     Test t; // local object     t.~Test(); // Explicit call to destructor     return 0; }

Output:

Constructor is executed
Destructor is executed
Constructor is executed
Destructor is executed
Destructor is executed 

When the constructor is called explicitly the compiler creates a nameless temporary object and it is immediately destroyed. That’s why 2nd line in the output is call to destructor.


we should never call destructor explicitly on local (automatic) object, because really bad results can be acquired by doing that.